**Question: **The following data (and partial analysis) on blood pressure was gathered at an employer health fair. A sample of 92 employees were screened and their blood pressures and sex were recorded (also pulse, height and weight). SYST= systolic pressure, DIAST = diastolic pressure (both in mm of mercury); SEX = 1 for males and 0 for females. Normally, a person’s systolic pressure is higher than his/her diastolic pressure. The company would like to know if there are any interesting patterns in this data.

OBS | SYST | DIAST | SEX | systdev | systdev2 | sexdev | sexdev2 | syst-sex |

1 | 108 | 78 | 1 | -13.96 | 194.78 | 0.4783 | 0.2287 | -6.6749 |

2 | 108 | 76 | 1 | -13.96 | 194.78 | 0.4783 | 0.2287 | -6.6749 |

3 | 108 | 68 | 0 | -13.96 | 194.78 | -0.5217 | 0.2722 | 7.2817 |

4 | 106 | 60 | 0 | -15.96 | 254.61 | -0.5217 | 0.2722 | 8.3251 |

5 | 124 | 90 | 1 | 2.04 | 4.18 | 0.4783 | 0.2287 | 0.9773 |

6 | 110 | 78 | 0 | -11.96 | 142.96 | -0.5217 | 0.2722 | 6.2382 |

7 | 126 | 84 | 0 | 4.04 | 16.35 | -0.5217 | 0.2722 | -2.1096 |

and | many | more … | ||||||

86 | 110 | 80 | 0 | -11.96 | 142.96 | -0.5217 | 0.2722 | 6.2382 |

87 | 104 | 70 | 0 | -17.96 | 322.44 | -0.5217 | 0.2722 | 9.3686 |

88 | 126 | 86 | 0 | 4.04 | 16.35 | -0.5217 | 0.2722 | -2.1096 |

89 | 172 | 114 | 1 | 50.04 | 2504.35 | 0.4783 | 0.2287 | 23.9338 |

90 | 150 | 100 | 1 | 28.04 | 786.44 | 0.4783 | 0.2287 | 13.4121 |

91 | 136 | 78 | 1 | 14.04 | 197.22 | 0.4783 | 0.2287 | 6.7164 |

92 | 112 | 70 | 0 | -9.96 | 99.13 | -0.5217 | 0.2722 | 5.1947 |

SUM | 11220 | 7502 | 48 | 0.00 | 23223.8 | 0.00 | 22.96 | 316.09 |

systdev = deviation from the mean systolic pressure

systdev2 = systdev squared

sexdev = deviation from the mean of sex

sexdev2 = sexdev squared

diasdev= deviation from the mean of diastoylic pressure

diasdev2 = diasdev squared

syst-sex = product of the deviations from the mean of systolic pressure and sex

S diasdev = 0.0 S diasdev2 = 9585.69 Sdiasdev*sysdev= 11190.25 Sdiasdev*sexdev = 287.17

a) Find the mean systolic pressure for the employees in this sample.

b) Find the standard deviation of systolic pressure for the employees in this sample.

c) Find the correlation coefficient between systolic pressure and sex for the employees in this sample.

d) Interpret the meaning/significance of the correlation coefficient found in part c. Why is this a useful piece of information?

**Solution:**The solution consists of 486 words (3 pages)

**Deliverables:**Word Document